181. Employees Earning More Than Their Managers
题目描述和难度
- 题目描述:
Employee
表包含所有员工,他们的经理也属于员工。每个员工都有一个 Id,此外还有一列对应员工的经理的 Id。
+----+-------+--------+-----------+ | Id | Name | Salary | ManagerId | +----+-------+--------+-----------+ | 1 | Joe | 70000 | 3 | | 2 | Henry | 80000 | 4 | | 3 | Sam | 60000 | NULL | | 4 | Max | 90000 | NULL | +----+-------+--------+-----------+
给定 Employee
表,编写一个 SQL 查询,该查询可以获取收入超过他们经理的员工的姓名。在上面的表格中,Joe 是唯一一个收入超过他的经理的员工。
+----------+ | Employee | +----------+ | Joe | +----------+
- 题目难度:简单。
- 英文网址:181. Employees Earning More Than Their Managers 。
- 中文网址:181. 超过经理收入的员工 。
思路分析
求解关键:
用于测试的 SQL 语句:
drop table if exists Employee;
create table Employee(
Id int primary key auto_increment,
Name varchar(200),
Salary int,
ManagerId int
);
insert into Employee(Id,name,Salary,ManagerId) values(1,'Joe',70000,3);
insert into Employee(Id,name,Salary,ManagerId) values(2,'Henry',80000,4);
insert into Employee(Id,name,Salary,ManagerId) values(3,'Sam',60000,NULL);
insert into Employee(Id,name,Salary,ManagerId) values(4,'Max',90000,NULL);
参考解答
参考解答1
select t1.Name as Employee from Employee t1,Employee t2
where t1.`ManagerId` = t2.`Id` and t1.`Salary` > t2.`Salary`;
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